512 | | \begin_layout Standard |
| 512 | \begin_layout Subsection |
| 513 | Test Scenarios |
| 514 | \end_layout |
| 515 | |
| 516 | \begin_layout Standard |
| 517 | With almost full information, design of the control strategy should be almost |
| 518 | trivial: |
| 519 | \begin_inset Formula \begin{eqnarray*} |
| 520 | \hat{\isa{}} & = & 0,\,\hat{\isb{}}=0,\hat{\omega}=1,\th=\frac{\pi}{2},\\ |
| 521 | P_{t} & = & \mathrm{diag}([0.01,0.01,0.01,0.01]).\end{eqnarray*} |
| 522 | |
| 523 | \end_inset |
| 524 | |
| 525 | |
| 526 | \end_layout |
| 527 | |
| 528 | \begin_layout Standard |
| 529 | The difficulty arise when growing covariance matrix: |
| 530 | \begin_inset Formula \begin{eqnarray*} |
| 531 | \hat{\isa{}} & = & 0,\,\hat{\isb{}}=0,\hat{\omega}=1,\th=\frac{\pi}{2},\\ |
| 532 | P_{t} & = & \mathrm{diag}([0.01,0.01,1,1]).\end{eqnarray*} |
| 533 | |
| 534 | \end_inset |
| 535 | |
| 536 | |
| 537 | \end_layout |
| 538 | |
| 539 | \begin_layout Standard |
| 540 | Or even worse: |
| 541 | \begin_inset Formula \begin{eqnarray*} |
| 542 | \hat{\isa{}} & = & 0,\,\hat{\isb{}}=0,\hat{\omega}=1,\th=\frac{\pi}{2},\\ |
| 543 | P_{t} & = & \mathrm{diag}([0.01,0.01,1,10]).\end{eqnarray*} |
| 544 | |
| 545 | \end_inset |
| 546 | |
| 547 | |